Pool, But Not As You Know It…
I invented a new game of pool the other day. I call it "Len always wins by default and not by actual skill", or LAWBDANBAS for short. Although the situation the title describes is also true of a regular game of 8 or 9 ball, they already have official names, and so I invented this game to call my own.
You need to set up the table as follows:
- The balls 1-6 just next to each pocket, in no particular order.
- The black ball, 8, on the spot
- The white ball in the middle of the D.
The aim of the game is to pot all the numbered balls in ascending order followed by the black. If you pot any of the balls out of order or pot the white, you lose and your opponent claims victory by default.
Yeah...
The Numbers are Crazy!
Maths is a funny subject. Pretty much everything we use has its roots in maths. Somehow. But strangely enough, the more you think about maths or any specific mathematic theory, the more absurd the whole concept becomes.
Take for instance the question: "Does 0.9 recurring = 1?" Of course not! I hear you cry, because they are both entirely different numbers and no matter how close they are to each other they still can't be the same. Right...?
Well, consider that the difference between .9 and 1 is .1, and also
from .99 to 1 is .01
from .999 to 1 is .001
from .9999 to 1 is .0001
from .99999 to 1 is .00001
and so on.
Since 0.9r goes on infinitely, we could say that the difference between .99r and 1, for example, is .0r + 1. By logic, this means that the "+1" is infinitely small in all cases and thus 0.9r = 1.
Another way of thinking about it, is that if you multiply 1/3 by 3 on a calculator (remembering that 1/3 = 0.3r), you don't get 0.9r, you get 1.
Still following me?
Things get confusing though when you begin to consider further, the reasoning behind the above proof.
If we assume for now that 0.9r = 1 thanks to the method shown above, that means after an infinite number of decimal places, the two numbers (0.9r and 1), which would normally be next to each other on a number line, are in fact equal. Based on this, you are basically saying that all consecutive numbers are equal, and thus implying that when you count from 1 to 10, you might as well be saying any random numbers...hmm...
Still not convinced?
Let x=0.9r (Equation 1)
10x=9.9r (Equation 2)
(2)-(1): 9x=9
Therefore x=1
Need more proof?
1/3 + 2/3 = 3/3 => 1/1 => 1
1/3 = 0.3r
2/3 = 0.6r
1/3 + 2/3 = 0.3r + 0.6r
0.3r + 0.6r = 0.9r
0.9r = 1/3 + 2/3 = 1
Crazy Numbers to be continued...